348. Design Tic-Tac-Toe
Design a Tic-tac-toe game that is played between two players on a n x n grid.
You may assume the following rules:
- A move is guaranteed to be valid and is placed on an empty block.
- Once a winning condition is reached, no more moves is allowed.
- A player who succeeds in placing
nof their marks in a horizontal, vertical, or diagonal row wins the game.
Example:
Given n = 3, assume that player 1 is "X" and player 2 is "O" in the board.
TicTacToe toe = new TicTacToe(3);
toe.move(0, 0, 1); -> Returns 0 (no one wins)
|X| | |
| | | | // Player 1 makes a move at (0, 0).
| | | |
toe.move(0, 2, 2); -> Returns 0 (no one wins)
|X| |O|
| | | | // Player 2 makes a move at (0, 2).
| | | |
toe.move(2, 2, 1); -> Returns 0 (no one wins)
|X| |O|
| | | | // Player 1 makes a move at (2, 2).
| | |X|
toe.move(1, 1, 2); -> Returns 0 (no one wins)
|X| |O|
| |O| | // Player 2 makes a move at (1, 1).
| | |X|
toe.move(2, 0, 1); -> Returns 0 (no one wins)
|X| |O|
| |O| | // Player 1 makes a move at (2, 0).
|X| |X|
toe.move(1, 0, 2); -> Returns 0 (no one wins)
|X| |O|
|O|O| | // Player 2 makes a move at (1, 0).
|X| |X|
toe.move(2, 1, 1); -> Returns 1 (player 1 wins)
|X| |O|
|O|O| | // Player 1 makes a move at (2, 1).
|X|X|X|
Follow-Up:
Could you trade extra space such that move() operation can be done in O(1)?
Solution:
class TicTacToe(object):
def __init__(self, n):
"""
Initialize your data structure here.
:type n: int
"""
self.size = n
self.board = [[0] * n for _ in xrange(n)]
self.rows = [0] * n
self.cols = [0] * n
self.diagonals = [0] * 2
def move(self, row, col, player):
"""
Player {player} makes a move at ({row}, {col}).
@param row The row of the board.
@param col The column of the board.
@param player The player, can be either 1 or 2.
@return The current winning condition, can be either:
0: No one wins.
1: Player 1 wins.
2: Player 2 wins.
:type row: int
:type col: int
:type player: int
:rtype: int
"""
self.board[row][col] = player
inc = 1 if player == 1 else -1
full = self.size * inc
self.rows[row] += inc
if self.rows[row] == full:
return player
self.cols[col] += inc
if self.cols[col] == full:
return player
if row == col:
self.diagonals[0] += inc
if self.diagonals[0] == full:
return player
if row == self.size - col - 1:
self.diagonals[1] += inc
if self.diagonals[1] == full:
return player
return 0